# What does main get?

In C, the `main` function typically takes two parameters: `argc` (argument count) and `argv` (argument vector). These parameters allow you to pass command-line arguments to your program.

Here's a simple example to illustrate how to use these parameters:

```c
#include <stdio.h>

int main(int argc, char *argv[]) {
    // Check if there are command-line arguments
    if (argc > 1) {
        // Print the program name
        printf("Program name: %s\n", argv[0]);

        // Print the command-line arguments
        printf("Arguments passed:\n");
        for (int i = 1; i < argc; i++) {
            printf("%d: %s\n", i, argv[i]);
        }
    } else {
        printf("No command-line arguments passed.\n");
    }

    return 0;
}
```

In this example, `argc` represents the number of command-line arguments, and `argv` is an array of strings containing those arguments. `argv[0]` is the program name, and the subsequent elements (`argv[1]`, `argv[2]`, etc.) are the actual command-line arguments.

Compile and run the program with command-line arguments to see how it works. For example:

```bash
./program_name arg1 arg2 arg3
```

In this case, `argc` would be 4, and `argv` would be an array containing the program name and the three arguments.

Keep in mind that the `main` function's signature must be one of the following:

```c
int main(void)
```

or

```c
int main(int argc, char *argv[])
```

The return type can be `void` or `int`, and `argv` is an array of strings (`char*`).